ValuexofX PXx 1 010 2 012 4 021 5 6 Fill in the values in
ValuexofX
P=Xx
1 0.10
2 0.12
4 0.21
5 _____
6 _____
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Solution
Since it is a discrete random variable therefore the sum of the probability must be equal to 1
P(X=1)+P(X=2)+P(X=4)+P(X=5)+P(X=6)=1
.10+.12+.21+P(X=5)+P(X=6)=1
P(X=5)+P(X=6)=.57
Divide that value in any way such that the sum is equal to .57
Here it is an example
| X | P(X) | 
| 1 | .10 | 
| 2 | .12 | 
| 4 | .21 | 
| 5 | .24 | 
| 6 | .33 | 

